Question

Calculate the amount of nh3 produced if2000g of dinitrogen reacts with 1000g dihydrogen

Answer 1

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(i) Balancing the given chemical equation,

From the equation, 1 mole (28 g) of dinitrogen reacts with 3 mole (6 g) of

dihydrogen to give 2 mole (34 g) of ammonia.

⇒ 2.00 × 103g of dinitrogen will react with dihydrogen i.e.,2.00 × 103g of dinitrogen will react with 428.6 g of dihydrogen.

Given,

Amount of dihydrogen = 1.00 × 103g

Hence, N2 is the limiting reagent.

28 g of N2 produces 34 g of NH3.

Hence, mass of ammonia produced by 2000 g of N2= 2428.57 g

(ii) N2 is the limiting reagent and H2 is the excess reagent. Hence, H2 willremain unreacted.

(iii) Mass of dihydrogen left unreacted = 1.00 × 103g – 428.6 g= 571.4 g