Calculate the amount of oxalic acid [(COOH)2.2H2O]in gram that is required to obtain 250 mL of a semi molar (M/2) solution
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If the solution is already made then few ml of this solution has to be titrated with known strength of base (NaOH) solution using indicator or with KMnO4 . Then use V1S1=V2S2 to calculate the strength. Here V1 & V2 are the volume of acid and base respectively. S1 & S2 are the strength in normality of acid and base respectively. Divide the normality by 2 to get molarity of oxalic acid.
If the solution is about to be made then find the mole number of oxalic acid.
Molecule weight of hydrated oxalic acid (COOH)2.2H2O is 126
Mole number, m = weight taken ÷ 126
The volume is 250 ml, 1/4 of 1000 ml, so molarity = m×4
Explanation:
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