Question

calculate the amount of oxalic acid required to obtain 250 ml of semi molar solution

Answer 1

Equivalent weight of oxalic acid is 63 gram

We are using 1.26 gram

Volume of the solution is 250 ml

Now,

Normality of oxalic acid=

(weight of acid×1000)/(eq. Weight×vol.of sol.)

= (1.26×1000)/(63×250)

=0.08 N

Normality of given solution is 0.08 normal. Reverse of question

Answer 2

Answer: The amount of oxalic acid required to obtain 250 ml of semi molar solution is 11.25 grams.

Explanation:

Molarity is defined as the number of moles present per liter of the solution.

$Molarity=\frac{\text{given mass of compound}}{\text{Molar mass of compound}\times \text{volume of solution in L}}$

Given : Molarity= 0.5 M

Volume of solution = 250 ml=0.25 L   (1 L=1000 ml)

Molar mass of oxalic acid $C_2H_2O_4$ = 90 g/mol

$0.5M=\frac{\text{given mass of compound}}{90g/mol}\times 0.25 L}$

${\text {Given mass of oxalic acid}}=11.25g$