Question

calculate the amount of oxygen gas and potassium chloride formed during the decomposition of 49 g of potassium chlorate

Answer 1

Answer:- 19.2 g oxygen and 29.8 g potassium chloride are formed.

Solution:- Decomposition of potassium chlorate takes place as:

$2KClO_3\rightarrow 2KCl+3O_2$

Molar mass of potassium chlorate is 122.55 gram per mol.

molar mass of oxygen is 32 gram per mol and molar mass of potassium chloride is 74.55 gram per mol.

Now we can calculate the grams of both the products using dimensional analysis as:

calculations for grams of oxygen:

$49g KClO_3(\frac{1mol KClO_3}{122.55g KClO_3})(\frac{3 mol O_2}{2 mol KClO_3})(\frac{32g O_2}{1 mol O_2})$

= 19.2 g of oxygen

Calculations for grams of potassium chloride:

$49g KClO_3(\frac{1mol KClO_3}{122.55g KClO_3})(\frac{2 mol KCl}{2 mol KClO_3})(\frac{74.55g KCl}{1 mol KCl})$

= 29.8 g KCl

Answer 2

Answer:

19.2 g oxygen and 29.8 g potassium chloride are formed.

Solution:- Decomposition of potassium chlorate takes place as:

2KClO_3\rightarrow 2KCl+3O_22KClO3→2KCl+3O2

Molar mass of potassium chlorate is 122.55 gram per mol.

molar mass of oxygen is 32 gram per mol and molar mass of potassium chloride is 74.55 gram per mol.

Now we can calculate the grams of both the products using dimensional analysis as:

calculations for grams of oxygen:

49g KClO_3(\frac{1mol KClO_3}{122.55g KClO_3})(\frac{3 mol O_2}{2 mol KClO_3})(\frac{32g O_2}{1 mol O_2})49gKClO3(122.55gKClO31molKClO3)(2molKClO33molO2)(1molO232gO2)

= 19.2 g of oxygen

Calculations for grams of potassium chloride:

49g KClO_3(\frac{1mol KClO_3}{122.55g KClO_3})(\frac{2 mol KCl}{2 mol KClO_3})(\frac{74.55g KCl}{1 mol KCl})49gKClO3(122.55gKClO31molKClO3)(2molKClO32molKCl)(1molKCl74.55gKCl)

= 29.8 g KCl