Question

calculate the amount of oxygen
required to form
44800 cm^3
of So2 gas?​

Answer 1

Answer:

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Explanation:

From ideal gas equation, PV=nRT.

Oxygen, V=1L,P=750mm Hg

Sulphur dioxide, V=2L,P=750mm Hg

Moles of O

2

⟹

RT

PV

=n

1

=

RT

1×1

Number of molecules =N=

RT

Na

⟶(i)

Similarly for SO

2

,

Moles of SO

2

=

RT

PV

=n

2

=

RT

1×2

Let number of molecules =M=

RT

2Na

⟶(2)

By dividing both eq.1 and eq.2 we get,

N

M

=2

M=2N