Calculate the amount of water (g) produced by the combustion of 16g of methane.
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Answered by
1
Answer:
One mole of CH4 (16 g) on combustion gives one mole of carbon dioxide and 2 moles of water and 2 moles of water = 2 x [2 + 16] = 36 g of water.
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Answer:
CH4 + 2 O2 ➡ CO2 + 2 H2O
1 mole methane - giving - 2 mole water
16 g methane - give --- 2 × 18 g water
so ,
16 g methane - give --- 36 g H20
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