Question

calculate the amount of water(H2O) formed during the complete combustion of 96g methane(CH4)(stoichiometric calculation)???

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Answer 1

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CH4+2O2 ⇒CO2+2H2O

1 mol CH4 =2 mol H2O

96 g CH4

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no. of moles = Given mass ÷ Gram molecular mass[GM/GMM]

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GM = 96 g

(C=12,H=1)

GMM=12×1+1×4=16u

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no. of moles⇒96÷16

⇒6 mol

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6 mol CH4 =2×6 mol H2O

=12 mol H2O

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no. of moles⇒GM/GMM

12⇒GM/18

GM =18 ×12

= 216 g

amount of water(H2O)⇒216 g

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