Question

calculate the amount of water produced by the combustion of 16 gram of Methane

Answer 1

Hi.

Reaction of the combustion of the methane is ⇒
 
CH₄ + O₂  ------------→ CO₂ + 2H₂O

Molar mass of the Methane = 16 g/mole.
Molar Mass of the Water = 18 g/mole.

From the Reaction,
∵ 1 mole of the Methane produces 2 moles of water.
∴ 16 grams of the Methane produces 2/16  = 1/8 moles of the water.

Now, No. of moles = Mass/Molar Mass.
∴ Mass of the water = No. of moles × Molar Mass.
∴ Mass of the water = 2 × 1/8
∴ Mass of the water = 2.25 grams.


Hence, the Mass of the water produces 2.25 grams of the water.


Hope it helps.