Question

calculate the amount of water required to prepare 500g of 2.5%solutions of sugar

Answer 1

Mass percent = mass of solute / mass of solution .

Where mass of solution = mass of solute +  mass of solvent

Here mass of solution = 500g

Mass percent = 2.5 % 

Let the mass of solute be x.

Then 2.5 %  = x / 500

⇒ x = 12.5g

Hence mass of sugar is 12.5 g

∴ mass of solvent = mass of solution - mass of solute

∴ mass of solvent = 500 g - 12.5g

⇒ mass of solvent = 487.5 g 

Hence 487.5 g of water is required to prepare 500g of 2.5 % sugar solution. 

Answer 2

Hey !

☆ Here is your answer ☆

Sugar=sucrose=C12 H22 O11

Molar mass =342

water=H2O , Molar maas=18

Assume that 2.5% sugar means percentage by weight.

In 500g of sugar solution , there are 500*2.5/100=12.5 grams of sugar.

So amount of water = 500 - 12.5= 487.5 grams



Hope this helps you ^_^