Question

calculate the amount of work done in bringing a point charge of 8 microcoulomb from point A toB .if electric potential are 2volt and 4volt respectively at A and B​

Answer 1

Answer:

The work done = 16 x 10^-6 J

Potential difference across Point A and B

= 4 - 2

= 2V

Charge = 8 microcoulomb

$8 \: \times \: {10}^{ - 6} \: coulombs$

V = W / q

=> W = qV

$= \: 8 \: \times \: {10}^{ - 6} \: \times \: 2 \\ = \: 16 \: \times \: {10}^{ - 6} \: joules$

Answer 2

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