Question

calculate the amount of work done in turning an electric dipole of dipole moment into 10 to the power minus 8 centimetre from its position of unstable equilibrium position of stable equilibrium in uniform electric field of intensity 10 to the power 3 Newton per coulomb​

Answer 1

Answer:

1*10^-5

Explanation:

work done is =pecosx

where

p is dipole moment

e is electrical field

cosx is angle btw dipole and electric field

so

work done=final-initial

at unstable equilbriu. angle btween electric field and dipole is 180 and at stable eqbm it is 90

Answer 2

I hope this might help you