Question

calculate the amount of work done is lifting a packet of 100 kgto the top of a building of height 10 m
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Answer 1

Answer:

Frictional force acting on it , =μm g=0.4×100×9.8=392 N

Given , Mass ,m=100 kg

Distance ,s=10 m

Work done , W=μmgs=392×1=3920 J

Answer 2

Answer:

hope it helps

Explanation:

ya but it's not mine,this answer was given by someone else.