Question

calculate the amount of work done to carry 4c of charge from a point at 100v to a point at 120v

Answer 1

V2=120v
V1=100
V=V2-V1
V=120v-100v=20v
$v = \frac{w}{q}$
w=v×q
w=20×4
w=80 joule

Answer 2

Given that,

Charge, q = 4 C

Voltage 1, V₁ = 100 V

Voltage 2, V₂ = 120 V

To find,

The amount of work done in moving charge.

Solution,

The work done in moving charge is given by the relation as follows :

$W=V\times q\\\\W=(V_2-V_1)\times q\\\\W=(120-100)\times 4\\\\W=80\ J$

Hence, the work done is 80 Joules.