Question

Calculate the amount of work done to draw a current of 8A from a point at 100V to a point at 120V in 2 seconds.

Answer 1

Answer:

final potential - initial potential = work done / charge

thus , charge = current × time = 16

net potential = 20 v

work done from the above formulae is ,

20 ×16 = work done

320 joule = work done

Answer 2

Concept:

Here, we need to apply the relationship in between work and potential difference which is given as, W = ΔV×q.

Given:

Current = 8A

Change in potential difference, ΔV = 120V -  1000 V = 20V

time = 2seconds

Find:

We need to determine the amount of work done.

Solution:

Work completed and potential differences are related as follows:

W = ΔV×q.

Here, q is the charge, and ΔV is the change in potential difference.

As charge is provided as, q = it Here, the current i is present, and the time is t.

Relation thus becomes,

W = ΔV × it

We have, ΔV = 20 V, current as 8 A and time as 2 seconds.

Therefore, formula of work done becomes,

W = 20 × 8×2

W = 320J

Thus,  the amount of work done is 320 J.

#SPJ2