Question

calculate the amount on a sum of rupees 15 ,000 at 12 percent pa compounded annually for 2y

Answer 1

Step-by-step explanation:

Answer

Given

Principal (P) = Rs 15000

Rate (R) = 10% p.a.

Period (n) = 2 years

Hence,

Amount (A) = P {1 + (R / 100)}

n

= Rs 15000 {1 + (10 / 100)}

2

On further calculation, we get,

= Rs 15000 × (11 / 10) × (11 / 10)

We get,

= Rs 18150

Therefore,

Compound interest = Amount – Principal

= Rs 18150 – 15000

We get,

= Rs 3150

Answer 2

$\bold{\large{\boxed{\red{\tt{ANSWER }}}}}$

$\purple{\tt{Principal \: (P) \: }} =15000$

$\pink{\tt{Rate \: of \: Intetest \: (R) }} =12 \: percent$

$\orange{\tt{Time \: (n) \: }} = 2 \: years$

$\boxed{\bold{\large{\blue{\tt{Amount = P {(1 + \frac{R}{100} )}^{n} }}}}}$

$\rightarrow15000 {(1 + \frac{12}{100} )}^{2}$

$\rightarrow15000 {( \frac{112}{100}) }^{2}$

$\rightarrow15000 \times \frac{112}{100} \times \frac{112}{100}$

$\rightarrow \: Rs \: 18816$

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