Question

Calculate the amount oxalic acid required to prepare 0.05M 50mL solution.[Molecular weight oxalic acid = 126g ​

Answer 1

Required molarity of solution=0.05 M

molarity=mols of solute/litres of solution

litres of solution= 50/1000 litres =>1/20 litres

RMM of H2C2O4= 126 g mol-1

let mols of solute be x mols.

x/(1/20)=0.05

20x=0.05

x=5/2000

x=1/400

x=0.0025 mol

mass of H2C2O4 required= 126 * 0.0025 g

mass of H2C2O4 needed=0.315 grams.

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