Question

calculate the amount when p=1000,R=10% per annum (compounded annually)Time 2 yeras​

Answer 1

Answer: 1210₹

Step-by-step explanation:

Given,

          principal = 1000

           Time (t) = 2 years

           Rate (n) = 10% per annum

     Amount = $P(1+\frac{r}{100} )^{n}$

                   $=1000(1+\frac{10}{100} )^{2}$

                   $=1000(1+\frac{1}{10})^{2}$

                   $=1000 (\frac{11}{10} )^{2}$

                   $=1000(\frac{121}{100} )$

                   = 10×121

                   = 1210 rs

∴ The amount is 1210 ₹

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Answer 2

Answer:

1

Step-by-step explanation:

Given,

principal = 1000

Time (t) = 2 years

Rate (n) = 10% per annum

Amount = P(1+\frac{r}{100} )^{n}P(1+

100

r

)

n

=1000(1+\frac{10}{100} )^{2}=1000(1+

100

10

)

2

=1000(1+\frac{1}{10})^{2}=1000(1+

10

1

)

2

=1000 (\frac{11}{10} )^{2}=1000(

10

11

)

2

=1000(\frac{121}{100} )=1000(

100

121

)

= 10×121

= 1210 rs

∴ The amount is 1210 ₹

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