Question

Calculate the angle between a 2n force and a 3n force so that their resultant is 4n

Answer 1

HELLO THERE!

Here, we need to apply the Vector concept.

Let the two force vectors be A and B.

|A| = 2N

|B| = 3N

Resultant R = 4N

We know,

$R = \sqrt{A^{2}+B^{2}+2ABcos\theta}$

Where θ is the angle between the two vectors A and B.

So,

$4 = \sqrt{(2)^{2}+(3)^{2}+2\times2\times3\times cos\theta} \\\\\implies 4 = \sqrt{13 + 12cos\theta} \\\\\implies 16 = 13 + 12cos\theta \\\\\implies 12cos\theta = 3 \\\\\implies cos\theta = \frac{1}{4} \\\\\implies \theta = cos^{-1}(\frac{1}{4})$

So, the angle between two forces should be cos⁻¹(1/4).

THANKS!

Answer 2

Answer:

Answer is given above.