Calculate the angle between the vectors A=2icap+2jcap-kcap and b=6icap-3jcap+6kcap
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A = 2 i + 2 j - k
B = 6 i - 3 j + 6 k
dot product: 12 - 6 - 6 = 0 = A * B * CosФ
That means that both vectors are perpendicular.
B = 6 i - 3 j + 6 k
dot product: 12 - 6 - 6 = 0 = A * B * CosФ
That means that both vectors are perpendicular.
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