calculate the angle marked with small letters in the following diagram
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Answer:
∠a = 40°
Step-by-step explanation:
according to question, ∠AOB = 100°
Then ∠DOC will also be 100° (vertically opposites are equal)
Sum of interior angle of ∆DCO = 180°
∠a = ∠DCO (Isosceles triangles have 2 equal sides and angles)
Let ∠a and ∠DCO be X because they're equal.
∠DOC + X + X = 180°
∠DOC + 2X = 180°
100° + 2X = 180°
2X = 180 ° - 100°
2X = 80°
X = 80°/2
X = 40°
∠a = 40° or
∠DCO = 40°
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