Calculate the angles of a triangle of ABC having 3 angle B=angle C and the interior angle A = 3/7 of exterior angle A
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A =(180-A )3/7
7A= 540 - 3A
10A = 540
A = 54.
Thus B+ C= 180 - 54 =126
But C =3B
thus 4B = 126
so, B = 31.5
and C = 94.5
hope tou like this
7A= 540 - 3A
10A = 540
A = 54.
Thus B+ C= 180 - 54 =126
But C =3B
thus 4B = 126
so, B = 31.5
and C = 94.5
hope tou like this
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