Question

Calculate the approximate kinetic energy of the gas molecules in 82.1 L flask at 27°C and 2 atm
pressure.
(1) 11.67 J
(2) 24.67 J
(3) 24.90 kJ
(4) 78.33 kJ

Here ans is option(3) but how??​

Answer 1

Answer:

Option (3)

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Answer 2

The approximate kinetic energy of the gas molecules is 24.90 kJ

Explanation:

According to the ideal gas equation:

PV=nRT

P = Pressure of the gas = 2 atm

V= Volume of the gas = 82.1 L

T= Temperature of the gas = $27^0C=(27+273) K=298K$      

R= Gas constant = 0.0821 atmL/K mol

$n=\frac{PV}{RT}=\frac{2\times 82.1}{0.0821\times 298}=6.71$

Average kinetic energy is defined as the average of the kinetic energies of all the particles present in a system. It is determined by the equation:

$K=\frac{3nRT}{2}$

R= gas constant = 8.314 J/Kmol

T= temperature in kelvin = 298 K

$K=\frac{3\times 6.71\times 8.314\times 298}{2}=24900J=24.90kJ$

Thus the approximate kinetic energy of the gas molecules is 24.90 kJ

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