Question

Calculate the area and the perimeter of the remaining portion after cutting tour quadrant each of radius 7 cm from the tour corners of a rectangle measuring 20cm by 30 cm

Answer 1

Area of rectangle = 30×20 =600cm^2. Each angle =90°. Theta=90° . Area of quadrant =πr^2theta/360°=22/7 ×7×7×90/360=22×7/4=77/2cm^2. Area of 4 quadrants= 4×77/2=154cm^2.Area of remaining portion of rectangle= 600-154=346cm^2. Now perimeter of rectangle =2(L+B)= 2×50=100.cm. NEW L =30-7-7=16andNEW B=20-7-7=6.New perimeter=2(l+b) =2×22==44cm . please solve now.