Question

calculate the area of a rhombus of side 13m with a shorter diagonal 10cm​

Answer 1

Answer:

To find out the area, first find the other diagonal :-

Given

Side of rhombus =13 cm

Length of first diagonal AC =10 cm (d1)

∴ OC=5 cm

Since, the diagonals of a rhombus bisect each other at right angles.

So, △BOC is right-angled.

Then, by Pythagoras Theorem we have :-

BC^2=OC^2+OB^2

⇒13^2=5^2+OB^2

⇒OB^2=169−25=144

⇒OB=12cm

Hence,

Diagonal BD =2×OB=2×12 =24 cm (d2).

Then, Area of rhombus :-

⇒1/2×d1×d2

⇒1/2×10×24

⇒12 cm^2

Step-by-step explanation:

HTH!¡! :)