Question

Calculate the area of a sector of angle 60°. Given, the circle is having a radius of 6 cm.​

Answer 1

132/7 cm^2

Given:

Sectors of an Angle = 60°

Radius of the Circle = 6 cm

To Find:

The area of the sector of an angle.

Calculating:

The formula that is used to calculate area of sector:

= (θ/360°)×π r^2

Substituting all the values that are given to us in this formula we get:

= 60/360 x 22/7 x 6 x 6

= 6 × 22/7

= 132/7 cm^2

Therefore, the area of the sector is 132/7 cm^2.

Answer 2

$\bf{\underline{\underline \blue{Solution:-}}}$

$\sf\underline{\red{\:\:\: AnswEr:-\:\:\:}}$

• The area of the sector of an angle = $\sf {\dfrac{132}{7} \:Cm^2}$

$\sf\underline{\red{\:\:\: Given:-\:\:\:}}$

• The Sectors of an Angle is 60°.
• And, the Radius of the Circle is 6 cm.

$\sf\underline{\red{\:\:\: Need\:To\: Find:-\:\:\:}}$

• The area of the sector of an angle = ?

$\bf{\underline{\underline \blue{Explanation:-}}}$

$\sf\underline{\red{\:\:\: Formula\:Used\: Here:-\:\:\:}}$

$\bigstar \: \boxed{ \sf \: Area \:of \: sector = \bigg(\dfrac{\emptyset}{360\degree}\bigg) \times \pi r^2}$

$\sf\underline{\green{\:\:\: Now,Putting\:the\: values:-\:\:\:}}$

$\dashrightarrow \sf {Area \:of \: sector = \dfrac{60}{360} \times \dfrac{22}{7} \times 6 \times 6}$

$\dashrightarrow \sf {Area \:of \: sector = 6 \times \dfrac{22}{7} }$

$\dashrightarrow \sf {Area \:of \: sector = \dfrac{132}{7} \:Cm^2}$

$\sf\underline{\green{\:\:\: Hence:-\:\:\:}}$

• The area of the sector of an angle = $\sf {\dfrac{132}{7} \:Cm^2}$

$\rule{200}{2}$