Calculate the area of a triangle whose adjacent sides are given by the vectors
A=2i-5j+8k and B=i+3j-4k.
Answers
Answered by
2
ANSWER
Area =
2
1
×∣A×B∣
A×B =15k−20j
∣A×B∣ =25
⟹ Area = 12.5
Answered by
0
Explanation:
Let
a
and
b
are adjacent side of a parallelogram, where
a
=2
i
^
+4
j
^
−5
k
^
and
b
=
i
^
+2
j
^
+3
k
^
Let diagonal be
c
Hence
c
=
a
+
b
=2
i
^
+4
j
^
−5
k
^
+
i
^
+2
j
^
+3
k
^
=3
i
^
+6
j
^
−2
k
^
magnitude of
c
=
3
2
+6
2
+2
2
=
9+36+4
=7
Unit vector in direction of
c
=
∣
c
∣
c
=
7
1
(3
i
^
+6
j
^
−2
k
^
)
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