Question

Calculate the area of air filled capacitor plate when the separation between
the plates is 50 cm and capacitance is 1.0 µF .

Answer 1

Answer ⇒ The area between the plates is 5.7 × 10⁴ m².

Explanation ⇒

Given conditions,

Separation between the plates of the Capacitor (d) = 50 cm.

Capacitance (C) = 1 µF

Using the formula,

 C = Aε₀/d

∴ 1 × 10⁻⁶ = A × 8.85 × 10⁻¹²/0.5

Thus,

A = 10⁶ × 0.5/8.85

∴ A = 0.057 × 10⁶

∴ A = 5.7 × 10⁴ m².

Hence, the area between the plates is 5.7 × 10⁴ m².

Hope it helps.

Answer 2

Answer:

C = Aε₀/d

∴ 1 × 10⁻⁶ = A × 8.85 × 10⁻¹²/0.5

Thus,

A = 10⁶ × 0.5/8.85

∴ A = 0.057 × 10⁶

∴ A = 5.7 × 10⁴ m².