Question

calculate the area of cross section of a wire if its length is 1.0m its resistivity of material of wire is 1.84*10to the power -6​

Answer 1

Solution :

$\bigstar \: \: \boxed{\sf R = \rho \dfrac{l}{A}}\: \: \bigstar$

$: \implies\sf 23 \: = \: 1.84 \: \times \: {10}^{ - 6} \: \times \: \dfrac{1}{A}$

$: \implies\sf A \: = \: \dfrac{1.84 \: \times \: {10}^{ - 6}}{23}$

$: \implies\sf A \: = \: \dfrac{184 \: \times \: {10}^{ - 8}}{23}$

$: \implies\underline{ \boxed{\sf A \: = \: 8 \: \times \: {10}^{ - 8} m^{2}}} \: \: \bigstar$

$\underline{\sf Therefore,\:the \: area \: of \: cross \: section \: of \: wire \: is \: \bf{ 8 \times 10^{-8}\:m^2}}.$