Question

Calculate the area of cross section of a wire of length 2m, its resistance is 25Ω and the resistivity of material of wire is 1.84*10-6 Ωm.​

Answer 1

$\boxed{\rm {\dfrac{ \dfrac{Resistance(R) = 25 \Omega}{</p><p>Length(l) = 2m} }{ \dfrac{Resistivity (\rho) = 1.84 \times {10}^{ - 6} }{Area(A) = ?}} } }$

$\rm A = \dfrac{ \rho \times l}{R}$

$\rm A= \dfrac{2 \times 1.84 \times {10}^{ - 6} }{25}$

$\rm A= \dfrac{2 \times 1.84 \times {10}^{ - 8} \times 100}{25}$

$\rm{\underline{\underline{ A=14.72 \times {10}^{ - 8}}}}$