Question

Calculate the area of quadrilateral ABCD in which angle ABD=90° , triangle BCD is an equilateral triangle of side 24cm and AD=26cm

Answer 1

or should also write like the this
Area of ABCD = 249.408 + 120
= 369 .41 cm²

Answer 2

Answer:

AD²= AB²+ BD²

26²=24²+ BD²

676=576+BD²

676-576=BD²

100=BD²

10=BD

Area of right angle triangle = ½× b× h= ½×10×24= 120 cm²

BDC is an equivalent triangle

area of equilateral triangle = root8/4×side²=

root 8/4×24×24= 144 root3

area of ABCD= area of ABD+ area of BCD = 144root3+ 120

= 249.408+120=369.41 cm²

Step-by-step explanation:

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