❤️Calculate the area of the designed region in the figure common between the two quadrant of circles of radius 8 cm each.✔️✌️
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lakshay9377:
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here your answer by friend
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♒hey mate here is your answer ✌♥✌♥
❣by the given condition❤
❤area required= 2(area of quadrant - area of triangle)❣
❣so A=2(((theta/360) ×πr²)-((1/2)×base×height )❤
❤=2(((90/360) ×(22/7)(8)²)-((1/2)×8×8 )❣
❣=2(((1/4) ×(22/7)(64))-((1/2)(64))❤
❤=2((22×16)/7)-32)❣
❣=2 (( 352-224 )/7 )❤
❤=256/7❣
❣=36.57142857142857cm²❤
❎hope it will be helpful to you ✔✔
➖mark me brainliest ✌✌✌
❣by the given condition❤
❤area required= 2(area of quadrant - area of triangle)❣
❣so A=2(((theta/360) ×πr²)-((1/2)×base×height )❤
❤=2(((90/360) ×(22/7)(8)²)-((1/2)×8×8 )❣
❣=2(((1/4) ×(22/7)(64))-((1/2)(64))❤
❤=2((22×16)/7)-32)❣
❣=2 (( 352-224 )/7 )❤
❤=256/7❣
❣=36.57142857142857cm²❤
❎hope it will be helpful to you ✔✔
➖mark me brainliest ✌✌✌
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