Question

calculate the area of the shaded region in the adjoining figure the quadrilateral ABCD is a square with side 10 cm each
$\pi$
is equal to 3.14 ​

Answer 1

Answer:

Step-by-step explanation:

Hope it helps you

Please mark as brainliest

Answer 2

Given :

Quadrilateral ABCD is a square of side 10 cm

Value of π = 3.14

To Find :

Area of shaded region i.e. Area of region AxDyA

Solution :

•Clearly , AyBD is a quadrant of radius r = 10 cm

•Area of quadrant AyBD =

1/4 Area of circle

•Area of quadrant AyBD = πr²/4

Area of quadrant AyBD = 3.14×(10)²/4

Area of quadrant AyBD =

314/4 cm² = 157/2 cm² = 78.5 cm²

•Now , Area of triangle ABD =bh/2

Area of triangle ABD =10×10/2

Area of triangle ABD = 50 cm²

•So, Area of region AxDA = Area of quadrant AyBD - Area of triangle ABD

•Area of region AxDA = 78.5 - 50

Area of region AxDA = 28.5 cm²

•Area of region AxDyA = Area of region AxDA + Area of region AyDA

•Area of region AxDyA = 28.5 + 28.5

Area of region AxDyA = 57 cm²