calculate the area of triangle formed by joining the point (4;0);(0,0) and (0,4)
Answers
Answered by
8
Here is the ans for ur ques
Hope u like it ...
Hope u like it ...
Attachments:
Answered by
9
Let the vertices of the triangle be A(4,0), B(0,0) and C(04).
x1 = 4,x2 = 0,x3 = 0, y1 = 0,y2 = 0, y3 = 4.
We know that Area of triangle ABC = 1/2|x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2)|
= 1/2|4(0 - 4) + 0(4 - 4) + 0(0 - 0)|
= 1/2|4(-4) + 0 + 0)|
= 1/2|(-16)|
= 8 sq.units.
Therefore the area of the triangle = 8 sq.units.
Hope this helps!
x1 = 4,x2 = 0,x3 = 0, y1 = 0,y2 = 0, y3 = 4.
We know that Area of triangle ABC = 1/2|x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2)|
= 1/2|4(0 - 4) + 0(4 - 4) + 0(0 - 0)|
= 1/2|4(-4) + 0 + 0)|
= 1/2|(-16)|
= 8 sq.units.
Therefore the area of the triangle = 8 sq.units.
Hope this helps!
Similar questions