Please help..! A car of mass 1000kg starts from rest and comes down an inclined slope. If it travels a distance of 300 m in 30 sec , calculate (a) acceleration and (b) force acting on the bus?
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13
SOLUTION =>
Mass of car = 1000kg
travels = 300m in 30 sec
Then , acceleration = v-u/t
300/30= 10m/s
10-0/30= 0.3m/s^2
force = accelaration (ans)
Mass of car = 1000kg
travels = 300m in 30 sec
Then , acceleration = v-u/t
300/30= 10m/s
10-0/30= 0.3m/s^2
force = accelaration (ans)
Answered by
13
PLS see the pic.
Remember force = mass × acceleration.
Remember force = mass × acceleration.
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Meu11:
but in this answer the formula s=ut +half at^2;F=ma will be used
Yep.whether my ans is right?
Don't know
can u please ans the question a bomb of mass 0.5kg in my all question
Buddy, I checked with s= ut + 1/2 at^2 formula...both are correct.I get the same ans.Have a nice day.
thank you
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