Question

Calculate the atmospheric pressure
measured by the barometer for a
given density of mercury as 13590
kg/m3.
​

Answer 1

Answer:

Density of mercury = 13600 kg per m cube

Relative density = density of mercury ÷ density of water

Relative density = 13600 ÷1000

Therefore relative density = 13.6

Explanation:

The density of mercury,

We need to find the relative density.

Since, the density of water is 1000 kg/m³. So, relative density is given by :

RD = 13.6

So, the relative density is 13.6. Hence, this is the required solution.

According to the question, the column of mercury in a biometer is 76 mm of Hg, now we have to calculate the atmospheric pressure if the density of mercury = 13600 kg/m^3

From the question, we know that pressure= h×d×g

where h=hight of the Mercury in the barometer

d= density of the mercury

g= acceleration due to gravity

and given p= 13.6×10^3 kg/m^3

g= 10 m/s^2

h=76cm=0.76 m

so the atmospheric pressure would be

p= 0.76×3.6×10^3×10

= 1.03×10^5

Hope This Answer Helps you to Gain Knowledge

Answer 2

Explanation:

Destiny of Mercury=13590 by per metre cube

Realative distiny=destiny of Mercury divided by

Destin y of water

Relative destiny=13590 divided by 1000

Realative distiny= 13.6

______________________________________

The destiny of mercury

We need to find the realative destiny

the Destiny of water is 1000 kg/m 3

RD====13.6

realative destiny is 13.6

the colum of the Mercury biometer is 76mm

we know that H×D×G

h=hight of the volume

d=destiny of the volume

g=accreation due to gravity

g=10m/s

h=76cm=0.76m

....it would be

p=0.76×3.6×10^3×10

...1.03×10^5

....Hope it helps

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