Question

Calculate the atomicity of a gas X [atomic no. 35.5] whose vapour density is equal to its relative atomic mass.​

Answer 1

Answer:

2

Explanation:

The given gas is chlorine (at.no17 atomic mass 35.5).

It's atomicity is 2 as it exists in diatomic gaseous state

Answer 2

Answer:

$\huge \underline{ \rm {given \: :}}$

Atomic Weight = 35.5

Vapour Density = Atomic Weight

$\sf\underline{ \rm \red{}}we \: know \: that \:$

$\sf{ \rm \red{atomicity = \frac{moecular \: weight}{atomic \: weight} }}$

Molecular Weight = 2× VD

Molecular Weight = 2×35.5

$\sf{ \rm \red{atomicity = \frac{2 \times 35.5}{35.5} }} \\ \\ \huge\sf{ \: \red {atomicity \: = \: 2 }}$