Question

calculate the average and total kinetic energy of 0.5 mole of an ideal gas at 0°c?

Answer 1

Average kinetics energy =

$\frac{3}{2} KT= \frac{3}{2} \times 1.38 \times {10}^{ - 23} \times 273 \\ \\ = 5.65 \times {10}^{ - 21} j$

Total kinetic energy of n mole of gas =

n × 3/2 RT

= 0.5 × 3/2 × 8.314×273

= 1.702 kj

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