Question

calculate+the+average+kinetic+energy+for+one+molecule+of+gas+at+constant+volume

Answer 1

c+t+a+k+e+flggkfgktdd

Answer 2

pressure exerted by one mole of gas

P = [1/3]pv^2

PV=[1/3]Mv^2

w.k.t , PV =RT

therefore,  [1/3]Mv^2 = RT

this implies, [1/3]Mv^2=[3/2]RT

>> [1/2]Nmv^2=[3/2]RT (since M=Nm)

>>[1/2]Mv^2=[3/2][R/N]T = [3/2]RT

therefore total random kinetic energy for one mole = [3/2]RT

and average kinetic energy per mole= [3/2]KT