Calculate the average molar mass of gaseous mixture weighing 360 g and containing 3.011×10^24 molecules of N2O , 2.5g molecules of N2 and also certain mass of ethene..
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Answer:
119.67 g
Explanation:
6.02×10^23 molecules of N2O = 44 g N2O
3.011×10^24 molecules of N2O
= (44×3.011×10^24) / 6.02×10^23
= 220.0730897 g N2O
mass of ethene =360 – (220.0730897+2.5)
=136.4269103 g ethene
Average molar mass of gaseous mixture
=(136.4269103+220.0730897+2.5) / 3
= 119.67 g
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