Calculate the average velocity of the particle whose position vector changes from r₁ = 5i + 6j to r₂ = 2i + 3j in a time 5 second.
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Average velocity is the ratio of total displacement to total time taken.
e.g., ∆v = ∆x/∆t
Here, ∆v denotes the average velocity , ∆x denotes the total displacement and ∆t is the total time taken.
Here, ∆x = final position - intial position
∆x = r₂ - r₁ = 2i + 3j - (5i + 6j) = -3i - 3j
And time taken, t = 5 sec
Now, ∆v = (-3i - 3j)/5 = (-3/5)i + (-3/5)j
Magnitude of ∆v = 3√2/5 = 3 × 1.414/5 =4.242/5 = 0.8484 m/s
e.g., ∆v = ∆x/∆t
Here, ∆v denotes the average velocity , ∆x denotes the total displacement and ∆t is the total time taken.
Here, ∆x = final position - intial position
∆x = r₂ - r₁ = 2i + 3j - (5i + 6j) = -3i - 3j
And time taken, t = 5 sec
Now, ∆v = (-3i - 3j)/5 = (-3/5)i + (-3/5)j
Magnitude of ∆v = 3√2/5 = 3 × 1.414/5 =4.242/5 = 0.8484 m/s
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