Question

calculate the binding energy of an alpha. (1) mass of neutron 1.008665 u​

Answer 1

Explanation:

The alpha particle has two proton and two neutron.

The combined mass of nuclei =net mass of proton + net mass of neutron =(2×1.007277)+(2×1.00866)=4.031874 amu

Binding energy = mass defect =4.031874−4.001265=0.0306amu=0.0306(931.48)=28.5MeV

Answer 2

Answer:

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