Calculate the boiling point of a solution containing 0. 520 g of glucose in 80.2 g of water.
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ΔTb=Kb x m
=Kb x WB/MB x 1000/WA
ΔTb= 0.52 x 0.52/180 x 1000/80.2
=270.4/14436=0.0187
Therefore Bp= 373+0.0187=373.0187K
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