Question

calculate the bond order of he2+​

Answer 1

Answer:

Bond Order = 1/2*(No. of MO in Bonding - No. of MO in Anti-bonding)

BO = 1/2*(2-2)=0

He(2e-)=sigma 1s2 < sigma*1s2

Answer 2

Answer:

Bond order of $H e_{2}^{+}$ is 0.5.

Explanation:

Formula for Bond order is : $\frac{1}{2}\left(N_{b}-N_{a}\right)$

Where $N_b$ is Number of Bonding molecular orbital Electrons, which is 2 for $H e_{2}^{+}$

$N_a$ is number of anti-bonding molecular orbital electrons, which is 1 for$H e_{2}^{+}$

Hence, the Bond order is = $\frac{1}{2}$  (2-1) which gives  $\frac{1}{2}$ as the answer.  

So, the bond order for $H e_{2}^{+}$ and $H e_{2}^{-}$ are $\frac{1}{2}$ which is 0.5.