Question

calculate the capacitance of a capacitor when dielectric slab is inrtoduced between the plates of capacitors​

Answer 1

Answer:

As the plates are square so length (l)= widith (w).

here, A=lw=l

2

→l=

A

There are two capacitors - one is air filled and other is dielectric filled and they are in parallel.

For air filled capacitor: area A

1

=(l−x)l=(

A

−x)

A

=(A−

A

x) and

Capacitance, C

1

=

d

A

1

ϵ

0

=

d

(A−

A

x)ϵ

0

For dielectric field capacitor: area A

2

=lx=

A

x and

Capacitance , C

2

=

d

A

2

ϵ

r

ϵ

0

=

d

A

xϵ

r

ϵ

0

The net capacitance is C=C

1

+C

2

=

d

(A−

A

x)ϵ

0

+

d

A

xϵ

r

ϵ

0

=

d

ϵ

0

(A−

A

x+ϵ

r

A

x)

Answer 2

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