Question

Calculate the capacity (vehicle per hour) of the road when reaction time of the driver is 2 seconds. The design speed is 80 kmph and average length of the vehicle is 6 m. Take coefcient of friction as 0.35.

Answer 1

Answer:653.06

Explanation:

SSD = 0.278*80*2+(0.278*80)/(2*9.81*0.35)

SSD= 116.50

capacity of the road (N) = 1000V/L+C

then, N=  (1000*80)/(116.50+6)

          N = 653.06

where, V = speed of vehicle in kmph

L= length of vehicle in meter

C = stooping sight distance of vehicle

Answer 2

The capacity of the road is, 653.06.

How is road capacity calculated?

• Using the relation, C = 1000*V/S, one can easily determine the Theoretical Maximum Capacity.
• Here, C = Capacity of a single lane, vehicle per hour. V = Speed, kmph; S = Average center to center spacing of vehicles, when they follow one behind the other as a queue or space headway.

What is the basic capacity of road?

• Basic capacity is the maximum number of vehicles (PCU) that can pass a given point on a lane or roadway during one hour under the most nearly ideal roadway and traffic conditions which can possibly be attained.

What does capacity mean in transportation?

• Transportation capacity means the number of passenger seats, according to manufacturer specifications, available on all of the pupil transportation vehicles owned by the school district, multiplied by two.

According to the question:

SSD = 0.278*80*2+(0.278*80)/(2*9.81*0.35).

SSD= 116.50.

capacity of the road (N) = 1000V/L+C.

then, N=  (1000*80)/(116.50+6).

         N = 653.06

where, V = speed of vehicle in kmph.

           L= length of vehicle in meter.

            C = stooping sight distance of vehicle.

Hence, the capacity of the road are 653.06.

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