Calculate the capillary effect in millimeters in a glass tube of 4mm diameter, when immersed in (i) Water (ii) Mercury.The temperature of the liquid is 200 c and the values of the surface tension of water and mercury in contact with air are 0.073575 N/m and 0.51N/m respectively. The angle of contact for water is zero and for that mercury is 1300 . Take density of water at 200 c. Take Density of water at 200c as equal to998 kg/m3 .
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Given Calculate the capillary effect in millimetres in a glass tube of 4 mm diameter, when immersed in (i) Water (ii) Mercury. The temperature of the liquid is 20 degree c and the values of the surface tension of water and mercury at 20 degree C in contact with air are 0.073575 N/m and 0.51 N/m respectively. The angle of contact for water is zero and for that mercury is 130 degree. Take specific weight of water as 9790 N / m^3
- Diameter of tube d = 4 mm = 4 x 10^-3 m
- So capillary effect with rise or depression h = 4 σ cos theta / ρ x g x d
- So σ = surface tension in kg f / m = 0.073575 N/m
- So theta = angle of contact = 0 degree and
- So ρ = density = 998 kg / m^3 at 20 degree C
- Now capillary effect for water will be
- So h = 4 x 0.73575 x cos 0 / 998 x 9.81 x 4 x 10^-3
- = 7.51 x 10^-3 m
- = 7.51 mm
- Now capillary effect for mercury will be
- So σ = 0.51 N/m
- So theta = 130 degree
- Now ρ = specific gravity x 1000
- = 13.6 x 1000
- = 13,600 kg / m^3
- So h = 4 x 0.51 x cos 130 / 13,600 x 9.81 x 4 x 10^-3
- = - 2.454 x 10^-3 m
- = - 2.45 mm
The negative sign shows the depression of capillary.
Reference link will be
https://brainly.in/question/13604077
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