Question

Calculate the coefficient of static friction
for an object of mass 50 kg placed on
horizontal table pulled by attaching a
spring balance. The force is increased
gradually it is observed that the object
just moves when spring balance shows
50N.​

Answer 1

F=m×a

a=F÷m

a=50÷50

a=1

Now,

F=u×N

u=F÷N

u=50÷50

u=1

Explanation:

I hope my answer is correct. But I tried my best to solve this. If aswer will find to wrong then I'm sorry

Answer 2

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F=m×a

a=F÷m

a=50÷50

a=1

Now,

F=u×N

u=F÷N

u=50÷50

u=1