Question

calculate the combined resistances of three resistances 4 ohm,6 ohm and 8 ohm connected in series​

Answer 1

Answer:

being in series combination

the combined resistance or equivalent resistance will be equal to the sum of resistances

= (4+6+8)ohm

=18 ohm

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Answer 2

Solution :-

Given ,

• Resistor 1 ( R₁ ) = 4 Ω
• Resistor 2 ( R₂ ) = 6 Ω
• Resistor 3 ( R₃ ) = 8 Ω
• Three resistors are connected in series

We need to find ,

• Equivalent resistance ( Rₙ ) = ?

As we know that , if ‘ n ’ number of resistors are connected in series

• Rₙ = R₁ + R₂ + R₃ …. Rₙ

Similarly

• Equivalent resistance = R₁ + R₂ + R₃

Substituting the values of R₁ , R₂ , R₃

⇒ Rₙ = R₁ + R₂ + R₃

⇒ Rₙ = 4 + 6 + 8

⇒ Rₙ = 18Ω

Hence , combined resistances of three resistors = 18Ω