Question

calculate the compound interest on 4000 rupees in one and half year at 10% per annum compounded half yearly​

Answer 1

Answer:

CI = Rs. 630.50

Step-by-step explanation:

Principal (P) = 4000

rate of interest (r) = 10%

years (n) = 1 1/2

Amount = P(1+r/200)^2n

= 4000(1+ 10/200)^2×3/2

= 4000(210/200)^3

= 4000×21/20 × 21/20 × 21/20

= 4630.5

Compound Interest = 4630.5 - 4000

= 630.50

Answer 2

Answer:

The compound interest  will be equal to 630.5 rupees.

Step-by-step explanation:

We have given, principal (P) = Rs.4000

Time = $=1\frac{1}{2}=\frac{3}{2} \;years$

Rate per annum = 10%

If the compound interest is half yearly, then the rate will be halved and time will be doubled.

So, the rate becomes (r) $=\frac{10}{2}=5\%$

Time became  (t)  $=\frac{3}{2}*2 = 3 \;years$

Amount (A) $=P(1+\frac{r}{100} )^t$

$A=4000(1+\frac{5}{100} )^3$

$A=4000(\frac{105}{100} )^3$

$A=\frac{9261}{2}$

A = Rs.4630.5

The compound interest = A - P

Compound interest = 4630.5 - 4000 = Rs.630.5

Therefore, the compound interest is equal to 630.5 rupees.