Question

Calculate the compound interest on rs 18000 at 10% per annum in two years

Answer 1

Compound intrest = 18000×(1+10/100)*2
= 18000×11/10×11/10
=21780

Answer 2

Answer:

Required Compound interest is 3780 rupees.

Explanation:

Here given,total money = 18000 rupees

Rate of interest = 10%

and time = 2 years.

Here we want to find Compound interest.

We know,

C.I$= p {(1 + \frac{r}{100}) }^{t} - p$

Where p is principal,r is rate of interest and t is time.

According to question,

$p = 18000 \: rupees$

$r = 10\%$

and $t = 2$

years.

So, C.I

$= 1800 0{(1 + \frac{10}{100}) }^{2} - 1800 0\\ = 18000( { \frac{110}{100} })^{2} - 18000 \\ = 18000 \times \frac{11}{10} \times \frac{11}{10} - 18000 \\ = 21780 - 18000 \\ = 3780$

Required Compound interest is 3780 rupees.